PCB trace width calculator
The minimum width of a copper trace for a current and temperature rise, the current a trace can carry, or how hot it gets, from the IPC-2221 formula for external and internal layers. It also gives the trace’s resistance, voltage drop and power loss.
Minimum width –
- Cross-section
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- Copper thickness
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- Trace temperature
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- Resistance
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- Voltage drop
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- Power loss
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How it works
IPC-2221 relates the current a trace carries to its cross-section and its temperature rise above ambient with a curve fit to the standard’s conductor chart:
I = k · ΔT0.44 · A0.725
- I is the current in amperes, ΔT the temperature rise in °C, and A the cross-section in square mils.
- k = 0.048 for external layers and 0.024 for internal layers.
- The width is A divided by the copper thickness, taken as 1.378 mil (35 µm) per oz/ft², the usual convention.
Solving for width rearranges the formula to A = (I / (k · ΔT0.44))1/0.725; solving for the rise gives ΔT = (I / (k · A0.725))1/0.44.
Resistance, voltage drop and power loss
For a trace of length L, R = ρ(T) · L / (w · t), with ρ(T) = 1.7241 × 10−8 Ω·m · (1 + 0.00393 · (T − 20 °C)), the resistivity and temperature coefficient of annealed copper (IEC 60028), at the trace temperature T = ambient + rise. The voltage drop is I·R and the power loss I2·R.
Source
IPC-2221, Generic Standard on Printed Board Design (formerly IPC-D-275). The constants are those widely reproduced from its conductor chart, for example in the notes of Advanced Circuits’ trace width calculator and on NinjaCalc.
Validity range
The chart behind the formula covers currents up to 35 A, widths up to 400 mil (10.16 mm), temperature rises of 10 to 100 °C and copper of 0.5 to 3 oz/ft². Outside that range the formula extrapolates, and the calculator says so.
Limits
- IPC-2221’s chart is old and generally conservative: real traces usually run cooler than it predicts, so the widths it gives are on the safe side.
- It ignores what most affects a real trace’s temperature: nearby copper planes, board thickness and material, other traces, vias, airflow and the board’s own temperature. It describes long traces with no special heat sinking, carrying a steady current.
- For traces in a vacuum or a potted assembly, use the internal-layer result for external layers too.
- IPC-2152 is the newer standard, built from measured charts that account for board thickness, planes and more. This calculator does not implement IPC-2152.
- The resistance assumes a rectangular cross-section of the nominal thickness; etched and plated traces differ somewhat.
Worked examples
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Width for 1 A at a 10 °C rise, 1 oz copper. External: A = (1 / (0.048 · 100.44))1/0.725 = 16.3 mil², so w = 16.3 / 1.378 = 11.8 mil (0.300 mm). Internal: 30.8 mil (0.781 mm). Both match published IPC-2221 tables.
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Width for 5 A at a 20 °C rise, 2 oz external, 50 mm long, 40 °C ambient. The width is 35.7 mil (0.908 mm). At 60 °C the trace measures 15.7 mΩ, so it drops 78.5 mV and dissipates 0.392 W.
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Current for a 20 mil (0.508 mm) trace, 1 oz external, 10 °C rise. A = 20 · 1.378 = 27.6 mil², so I = 0.048 · 100.44 · 27.60.725 = 1.46 A. Over 100 mm at 35 °C: 103 mΩ, 0.150 V and 0.220 W.